the question is find the value of a and b i) 5+2√3 upon7+4√3= a-6√3
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the question is find the value of a and b i) 5+2√3 upon7+4√3= a-6√3
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(5 + 2√3 ) / ( 7 + 4√3 )=a-6√3
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- Find the value of a and b
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LHS = (5 + 2√3 ) / ( 7 + 4√3 )
rationalize the denominator
= (5 + 2√3 )( 7 - 4√3 )/[( 7 + 4√3 )( 7 -4√3 )
= [ 5 ×7 - 5 × 4√3 + 2√3 × 7 - 2√3 × 4√3 ] / [ (7 )² - (4√3 )² ]
Applying in the identity
( x + y ) (x - y ) = x² - y²
Putting the all values:-
= [35 -20√3 + 14√3 -24 ] / [ 49 - 48 ]
= (11 - 6√3 )
Therefore:-
,LHS = RHS
=11 - 6√3
= A - B√3 (Comparing both sides)
A = 11,
B = 6
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