The question is in the attachment given. Please answer.
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Answer:
(i) u = -29.4 m/s
(ii) S = 44.1 m
(iii) S = 39.2 m
Explanation:
Total time took in journey of ball = 6 sec
g = 9.8 m/s²
The speed of ball at highest point becomes = v = 0 m/s
Time took to reach the highest point = t/2 = 3 sec
We know,
v = u + at
(i) 0 = u + 9.8(3)
u = - 29.4 m/s (against gravity)
We know,
S = ut + 1/2 at²
(ii) S = (-29.4)(3) + 1/2(9.8)(3)²
S = -88.2 + 44.1
S = 44.1 m
Position after 4 sec = Maximum height - Distance travelled in 1 sec
(iii) S = 44.1 - [ut + 1/2at²] (As u = 0)
S = 44.1 - [1/2(9.8)(1)²]
S = 44.1 - 4.9
S = 39.2 m
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