Math, asked by pandeynikhil4208, 4 months ago

The question is there in the attachment.

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Answered by srushti9809

Answer:

The angle between a tangent and radius is right angle BNQ and AMP are right angles The triangle PAM is a right angled triangle with PA being the hypotenuse using phythogoros theorem the radius of the circle with centre A is found as

Step-by-step explanation:

given Qt=3cm ,PS=12cm , AP=13cm, BQ=5cm . Co struction join BN and AM In<AMP of (1)circle =90° Am^2=(17)^2_(15)^2 = 283_225/AM sqrt 64 =8cm AM=8cm=r PX=17+8=25 In second <ANO =90 BN^2=(13)^2_(12)^2 BN^2=25 BN= 5 cm therefore distance between A and B Ax + Bx=8+5 = 13 cm hope this may help you

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The question is there in the attachment.​

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given Qt=3cm ,PS=12cm , AP=13cm, BQ=5cm . Co struction join BN and AM In<AMP of (1)circle =90° Am^2=(17)^2_(15)^2 = 283_225/AM sqrt 64 =8cm AM=8cm=r PX=17+8=25 In second <ANO =90 BN^2=(13)^2_(12)^2 BN^2=25 BN= 5 cm therefore distance between A and B Ax + Bx=8+5 = 13 cm hope this may help you

The question is there in the attachment.