Question

the racing car has a uniform acceleration of 4 metre per second square the distance covered by the car in 10 second after the start is​

Answer 1

given :-

initial velocity = u = 0m/s

acceleration = 4m/s²

time = t = 10 seconds

by third equation of motion we get,

➡ s = ut + 1/2 at²

therefore the distance covered by the car after 10 seconds = ut + 1/2 at²

= (0 × 10) + 1/2 × 4 × (10)²

= 2 × 100

= 200m

hence, the distance covered by the racing car after 10 seconds is 200m.

Answer 2

$\huge\underline\mathfrak{Explanation}$

Given :

Acceleration (a)=4m/s²

Time (t) = 10s

Initial velocity (u) = 0

To find :

☑️ Distance covered by car

Solution :

S = ut + 1/2at² ( By second equation of motion )

S = 0×10+1/2(4)(10)²

S = 2×100

S = 200m

Hence, the distance covered by the car in 10 second after the start is 200m.

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