Question

The radii of circular ends of a bucket of height 24 cmare 15 cm and 5 cm. Find the area of its curved surface.

Answer 1

answer..............................

Answer 2

Given, height h = 24 cm, r₁ = 15 cm and r₂ = 5 cm.

We know that Slant height (l²) = h² + r²

⇒ l² = (24)² + (15 - 5)²

⇒ l² = 576 + 100

⇒ l² = 676

⇒ l = √676

⇒ l = 26 cm.

We know that curved surface area of frustum = π(r₁ + r₂)l

⇒ (22/7) * (5 + 15) * 26

⇒ (22/7) * (20) * 26

⇒ (22/7)[520]

⇒ 1634.28 cm^2.

Therefore, area of its curved surface = 1634.28 cm^2.

Hope it helps!