Physics, asked by puneetsharmabtp2004, 9 months ago

the radii of curvature of a convex lens are 20 cm and 30 cm. the refractive index of the substance of lens is 1.5 . if lens is kept in water 1.33 , then find focal length?​

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Answered by barotgopal
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Answer:

Brainly.in

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JayRandhawa

JayRandhawa

1 week ago

Physics

Secondary School

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The radii of curvature of a convex lens are 20 cm and 30 cm. The refractive index of the substance of lens is 1.5. If lens is kept in water(1.33) then find focal length.

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eklavyaarora2008

eklavyaarora2008 Ambitious

Answer:

From lens maker's formula, f1=(μ−1)(R11−R21)

We have,

Refractive index, μ=1.5 and R1=20 cm and R2=30 cm

f1=(1.5−1)(R11−R21)

f1=(1.5−1)(−201−−301)

f1=(1.5−1)20×30−30+20

f=−120cm

I hope it helps you to understand.

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