the radii of curvature of a convex lens are 20 cm and 30 cm. the refractive index of the substance of lens is 1.5 . if lens is kept in water 1.33 , then find focal length?
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JayRandhawa
JayRandhawa
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The radii of curvature of a convex lens are 20 cm and 30 cm. The refractive index of the substance of lens is 1.5. If lens is kept in water(1.33) then find focal length.
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eklavyaarora2008
eklavyaarora2008 Ambitious
Answer:
From lens maker's formula, f1=(μ−1)(R11−R21)
We have,
Refractive index, μ=1.5 and R1=20 cm and R2=30 cm
f1=(1.5−1)(R11−R21)
f1=(1.5−1)(−201−−301)
f1=(1.5−1)20×30−30+20
f=−120cm
I hope it helps you to understand.
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