Question

The radii of ends of a frustum are 14cm and 6cm respectively and its height is 6cm find its total surface area(pie 3.14). Pls do it fast

Answer 1

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Given:Radii are 14cm and 6cm

So, Let R be 14 and r be 6cm

Height=6cm

π=3.14

To find: Total surfaces area

Total surface area of frustum is

=π (R+r)l+πR^2+πr^2

Now first find the slant height.

L=√h^2+(R-r)^2

L=√6^2+(14-6)^2

L=√36+64

L=√100

L=10

So, SLANT HEIGHT is 10cm

Putting to the formula

=π(R+r)L+πR^2+πr^2

=3.14(14+6)10+3.14×14^2+3.14×6^2

=3.14×200+3.14×196+3.14×36

=3.14(200+196+36)

=3.14×432

=

$1356.48cm ^{2}$

So, total surface area of frustum is

$1356.48cm ^{2}$