The radii of the ends of a bucket 16 cm height are 20 cm and 8 cm. The curved surface area of the bucket is
(a)1760 cm²
(b)2240 cm²
(c)880 cm²
(d)3120 cm²
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Answer:
The Curved surface area of a Bucket is 1760 cm².
Among the given options option (a) 1760 cm² is the correct answer.
Step-by-step explanation:
Given :
Height of a conical bucket, (h) = 16 cm
Bigger Radius, R = 20 cm
Smaller Radius, r = 8cm
Slant height of a bucket , l = √(R - r)² + h²
l = √(20 - 8)² + 16²
l = √12² + 16²
l = √(144 + 256)
l = √400
l = 20 cm
Slant height of a frustum,l = 20 cm
Curved Surface area of a Bucket = π(R+ r)l
= π(20 + 8) × 20
= π(28 × 20 )
= 22/7 × 560
= 22 × 80
= 1760 cm²
Curved Surface area of a Bucket = 1760 cm²
Hence, the Curved surface area of a Bucket is 1760 cm².
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