The radii of the ends of a frustum
of a cone 45 cm high are 28 cm and 7 cm. Find its volume, the curved
surface area and the total suface area
(Take π=22/7)
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given: height of the frustum =45cm
radii = 28 and 7cm
sol. volume of frustum= 1/3πh((R)²+(r)²+(R*r))
=1/3*22/7*45((28)²+(7)²+(28*7)
=22/7 * 15 ((784) + (49) + (196)
=330/7 ( 1029)
=330 (147)
= 48510
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