The radii of two circles are 19 and 9cm respectively. Find the radius of circle which has circumference equal to the sum of circumference of the two circles.
Answers
Answer:
Step-by-step explanation:
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Radius (r1) of 1st circle = 19 cm
Radius (r2) or 2nd circle = 9 cm
Let the radius of 3rd circle be r.
Circumference of 1st circle = 2πr1 = 2π (19) = 38π
Circumference of 2nd circle = 2πr2 = 2π (9) = 18π
Circumference of 3rd circle = 2πr
Given that,
Circumference of 3rd circle = Circumference of 1st circle + Circumference of 2nd circle
2πr = 38π + 18π = 56π
→ r = 28 CM ________answer
Therefore, the radius of the circle which has circumference equal to the sum of the circumference of the given two circles is 28 cm.
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SOLUTION
Let the radius of first and second circle be
Let the radius of first and second circle ber1= 19cm and r2= 9cm
Sum of circumference
=) 2πr1 +2πr2
=) 2× 22/7×19 + 2×22/7 ×9
=) 2× 22/7( 19+9)
=) Now, let R be the radius of the new circle.
Then sum of circumference = circumference of new circle.
=) 2× 22/7(19+9)= 2× 22/7× R
=) R= 28cm
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