the radii of two circles are 25 cm and 18 cm find the radius of the circle which has circumference is equal to the sum of circumference is of these two circles
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the radius will be near about 43cm
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The radius of the 1st circle = 19 cm (given)
∴ Circumference of the 1st circle = 2π×19 = 38π cm
The radius of the 2nd circle = 9 cm (given)
∴ Circumference of the 2nd circle = 2π×9 = 18π cm
So,
The sum of the circumference of two circles = 38π+18π = 56π cm
Now, let the radius of the 3rd circle = R
∴ The circumference of the 3rd circle = 2πR
It is given that sum of the circumference of two circles = circumference of the 3rd circle
Hence, 56π = 2πR
Or, R = 28 cm.
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