Question

the radii of two circular cylinder are the ratio 2:3 and their heights are in the ratio 5:4 find the ratio of their c. s. a.​

Answer 1

Answer:

c.s.a of 1 cylinder=2πrh,=2π2×5=2π10

c.s.a of 2nd cylinder=2πrh=2π4×3=2π12

ratio of c.s.a of 1 cylinder and 2nd cylinder=10/12=5/6=5:6

Answer 2

Answer:

$= \frac{5}{6}$

Step-by-step explanation:

Let radius of:

I Cylinder = r1

II Cylinder = r2

$\frac{r1}{r2} = \frac{2}{3}$

Let height of:

I Cylinder = h1

II Cylinder = h2

$\frac{h1}{h2} = \frac{5}{4}$

CSA of:

I Cylinder =

$2\pi \: r1 \: h1$

II Cylinder =

$2\pi \: r2 \: h2$

ATQ

Ratio of I Cylinder to that of II Cylinder is:

$= \frac{2\pi \: r1 \: h1}{2\pi \: r2 \: h2} \\ \\ = \frac{r1}{r2} \times \frac{h1}{h2} \\ \\ = \frac{2}{3} \times \frac{5}{4} \\ \\ = \frac{5}{6}$

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