The radii of two circular ends of frustum shape bucket are 14 cm and 7 cm. Height of the bucket is 30 cm. How many liters of water it can hold ? (1 litre = 1000 cm3)
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Answered by
13
Volume=1/3×22/7×30(14×14+7×7+14×7)
. =22/7×10(196+49+98)
=220/7(343)
=220×49
=10780cu.cm
as,1 litres=1000cu.cm
10780/1000=10.780litres
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. =22/7×10(196+49+98)
=220/7(343)
=220×49
=10780cu.cm
as,1 litres=1000cu.cm
10780/1000=10.780litres
hope it helped u plz mark as brainliest
Answered by
2
Answer:
10.78 Litre
Step-by-step explanation:
If We extend it till a point then we can have two cones
Small cone with
height = x cm
radius = 7 cm
Larger cone
height = x + 30 cm
Radius = 40 cm
7/14 = x/(30+x) (similar triangles)
=> 30 + x = 2x
=> x = 30
Volume of bucket = Volume of Larger cone - Volume of Smaller cone
=> Volume of bucket = (1/3)π14²(30 + 30) - (1/3)π7²*30
π = 22/7
=> Volume of bucket = 22 * 14 * 2 * 20 - 22*7*10
= 12320 - 1540
= 10780 cm³
Capacity in litre = 10780/1000 = 10.78 Litre
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