Question

The radii of two concentric circles are 13cm and 8cm ab is the diameter of bigger circle and bd is a tangent to the smaller circle touching it at d and intersecting the larger circle at p on producing find the length of ap

Answer 1

Please see the attachment

Answer 2

Answer:

16 cm

Step-by-step explanation:

from right triangle BOD

BD = √(OB²-OD²) = √(13²- 8²) = √105

from right triangle POD

PD = √(OP²-OD²) = √(13²-8²) =  √105

PB = BD + PD = 2√105  PB²= 420

from right triangle APB

AP = √(AB²- PB²) =√26²- 420 = √676-420 = √256 = 16