The radii of two concentric circles are 13cm and 8cm ab is the diameter of bigger circle and bd is a tangent to the smaller circle touching it at d and intersecting the larger circle at p on producing find the length of ap
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Answer:
16 cm
Step-by-step explanation:
from right triangle BOD
BD = √(OB²-OD²) = √(13²- 8²) = √105
from right triangle POD
PD = √(OP²-OD²) = √(13²-8²) = √105
PB = BD + PD = 2√105 PB²= 420
from right triangle APB
AP = √(AB²- PB²) =√26²- 420 = √676-420 = √256 = 16
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