the radii of two concentric circles are 13cm and 8cm. ab is a diameter of the bigger circle and bd is a tengent to the smaller circle touching it at d and intersecting the larger circle at p on producing. find the length of ap
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R= 8cm
R=13cm
angle ODB= 90 degrees ( BD is tangent)
angle APB =90 degrees ( angle in semicircle)
angle DB0 =ANGLE PBA (COMMON)
SO, BY AA criteria tri APB similar to tri DBO
BY CPST ...... BD/BP=BO/AB= OD/ AP
OD/AP= BO/AB
8/AP=13/26
AP=16 cm
R=13cm
angle ODB= 90 degrees ( BD is tangent)
angle APB =90 degrees ( angle in semicircle)
angle DB0 =ANGLE PBA (COMMON)
SO, BY AA criteria tri APB similar to tri DBO
BY CPST ...... BD/BP=BO/AB= OD/ AP
OD/AP= BO/AB
8/AP=13/26
AP=16 cm
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