the radii of two cylinders are in the ratio 2:3 and their height are in the ratio 5:3 .calculate the ratio of their curved surface areas.
Answers
Answered by
144
let 2x and 3x be the radii of the two cylinders
and their height be 5y and 3y respectively
now
C.S.A of first cylinder (a) = 2 × 22/7 × 2x × 5y
C.S.A of second cylinder (b) = 2 × 22/7 × 3x × 3y
ratio of them = a/b
= (2 × 22/7 × 2x × 5y)/(2 × 22/7 × 3x × 3y)
= 10xy / 9xy
= 10/9
therefore their C.S.A are in the ratio 10/9
and their height be 5y and 3y respectively
now
C.S.A of first cylinder (a) = 2 × 22/7 × 2x × 5y
C.S.A of second cylinder (b) = 2 × 22/7 × 3x × 3y
ratio of them = a/b
= (2 × 22/7 × 2x × 5y)/(2 × 22/7 × 3x × 3y)
= 10xy / 9xy
= 10/9
therefore their C.S.A are in the ratio 10/9
Answered by
50
Answer:
Ratio of CSA=10/9 AND Ratio of Volume=20/27
Step-by-step explanation:
Let the radii of the cylinders be 2x and 3x respectively.
And let their heights be 5y and 3y respectively.
CSA of 1st cylinder=2πrh=2π×2x×5y
CSA of 2nd cylinder=2πRH=2π×3x×3y
∴Ratio of CSA of the 2 cylinders=2π×2x×5y÷2π×3x×3y
=10xy÷9xy
=10/9
Volume of 1st cylinder= πr²h=π×4x²×5y
Volume of 2nd cylinder= πR²H=π×9x²×3y
∴Ratio of the volume of the 2 cylinders=π×4x²×5y÷π×9x²×3y
=4×5÷9×3=20÷27=20/27
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