Physics, asked by Shafii, 1 year ago

The radii of two soap bubbles are R1 nd R2 respectively.The ratio of masses of air in them will be :

Answers

Answered by Percy1Jackson
7
hope this helps any doubts please comment
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Answered by gadakhsanket
0

Dear Student,

◆ Answer -

M1/M2 = (r1/r2)^3

● Explanation -

Mass of 1st soap bubble is -

M1 = V1 × d

M1 = 4/3 πr1^3 × d

Mass of 2nd soap bubble is -

M2 = V2 × d

M2 = 4/3 πr2^3 × d

Ratio of masses of air in soap bubbles is given by -

M1/M2 = (4/3 πr1^3 × d) / (4/3 πr2^3 × d)

M1/M2 = (r1/r2)^3

Thanks dear. Hope this helps you...

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