The radii of two soap bubbles are R1 nd R2 respectively.The ratio of masses of air in them will be :
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Dear Student,
◆ Answer -
M1/M2 = (r1/r2)^3
● Explanation -
Mass of 1st soap bubble is -
M1 = V1 × d
M1 = 4/3 πr1^3 × d
Mass of 2nd soap bubble is -
M2 = V2 × d
M2 = 4/3 πr2^3 × d
Ratio of masses of air in soap bubbles is given by -
M1/M2 = (4/3 πr1^3 × d) / (4/3 πr2^3 × d)
M1/M2 = (r1/r2)^3
Thanks dear. Hope this helps you...
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