Question

Construct a triangle abc in which bc = 6 cm,ab = 5.2 and ac = 4.8 cm. give me only step of construction. please fast

Answer 1

Hii friend,

Step of construction of your question is:-

(1) Draw a line segment BC = 6 cm

(2) With B as center and radius equal to 5.2 cm draw an arc.

(3) Then C as center and radius equal to 4.8 cm, draw another arc, which cutting the previous arc at a point A.

(4) Then Join AB and AC.

Then, ∆ABC is the required triangle. In which AB = 5.2 cm , BC = 6 cm and AC = 4.8 cm


HOPE IT WILL HELP YOU...... :-)

Answer 2

1. Consider that BC is base.

2.Draw line BC= 6 cm.

3.From point B draw an arc of 5.2 cm.

4.Now, from point C draw an arc of 4.8 cm.

5.The point where those two arcs intersect will be point A.

6.Join BA and CA.

ABC is the required triangle.