The radius and height of a circular cone are in the ratio of 3:7 . If its volume is 528 cm3 find the slant height and the radius of tje base.
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let the radius and cone be 3x and height be 7x
volume of cone =1/3pir^2h
1/3×22/7×3x×3x×7x=528
66x^3=528
x^3=528/66
x^3= 8
x= 2
therefore, height = 7×2=14cm
radius= 3×2=6
slant height of cone= whole under root r^2+h^2
whole under root (14)^2+ (6)^2
whole under root 196+36=root 232=15.23cm
here is the answer mate hope it helps you.
please mark it as brainliest.
volume of cone =1/3pir^2h
1/3×22/7×3x×3x×7x=528
66x^3=528
x^3=528/66
x^3= 8
x= 2
therefore, height = 7×2=14cm
radius= 3×2=6
slant height of cone= whole under root r^2+h^2
whole under root (14)^2+ (6)^2
whole under root 196+36=root 232=15.23cm
here is the answer mate hope it helps you.
please mark it as brainliest.
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