The radius and height of a right circular cone are in the ratio 3:4 and it's volume is 2156cm. Find the CSA and TSA of the cone
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Here is your answer ... ⬇⬇
let radius and height of the cone be( r ) and( h ) respectively.
Given that ratio of radius and height is 3:4
so,
r/h = 3/4
h = 4r/3 ------- ( 1 )
Volume of Cone is 2156 cm^3.
Volume = 2156
1/3 πr^2 h = 2156
1/3 × 22/7 × r^2 × 4r/3 = 2156
88r^3 = 2156 × 63
88r^3 = 135828
r^3 = 135828/88
r^3 = 1543.5
r = 11.55 cm
Put the value of ( r ) in eq. ( 1 )
h = 4( 11.55 )/3
h = 46.2/3
h = 15.4 cm
Now, find slant height ( l ).
l^2 = r^2 + h^2
l^2 = ( 11.55 )^2 + ( 15.4 )^2
l^2 = 133.4 + 237.16
l^2 = 370.56
l = √370.56
l = 19.24 cm
Find C.S.A
C.S.A = πrl
= 22/7 × 11.55 × 19.24
= 4888.88/7
= 698.41 cm^2
Find T.S.A
T.S.A = πr ( l + r )
= 22/7 × 11.55 ( 19.24 + 11.55 )
= 254.1/7 (30.79 )
= 254.1 × 4.39
= 1115.49 cm^2
HOPE IT HELPS YOU.....
THANKS ^-^
Here is your answer ... ⬇⬇
let radius and height of the cone be( r ) and( h ) respectively.
Given that ratio of radius and height is 3:4
so,
r/h = 3/4
h = 4r/3 ------- ( 1 )
Volume of Cone is 2156 cm^3.
Volume = 2156
1/3 πr^2 h = 2156
1/3 × 22/7 × r^2 × 4r/3 = 2156
88r^3 = 2156 × 63
88r^3 = 135828
r^3 = 135828/88
r^3 = 1543.5
r = 11.55 cm
Put the value of ( r ) in eq. ( 1 )
h = 4( 11.55 )/3
h = 46.2/3
h = 15.4 cm
Now, find slant height ( l ).
l^2 = r^2 + h^2
l^2 = ( 11.55 )^2 + ( 15.4 )^2
l^2 = 133.4 + 237.16
l^2 = 370.56
l = √370.56
l = 19.24 cm
Find C.S.A
C.S.A = πrl
= 22/7 × 11.55 × 19.24
= 4888.88/7
= 698.41 cm^2
Find T.S.A
T.S.A = πr ( l + r )
= 22/7 × 11.55 ( 19.24 + 11.55 )
= 254.1/7 (30.79 )
= 254.1 × 4.39
= 1115.49 cm^2
HOPE IT HELPS YOU.....
THANKS ^-^
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