the radius and height of the cone are in the ratio 3:4 and its volume is 301. 44cm^3.find the radius and slant height of the cone
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let the common factor be x So radius and height would be 3x and 4 x respectively. Volume of cone is 1/3 pi*r^2*h so, 301.44=1/3 pi*36x^3 find appropriate value for x and then for slant height use pythagoras formula. after finding x,multiply x by 3 to get radius and by 4 to get height. Now by pythagoras theorem, r^2 +h^2 =l^2
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Hey mate here is your answer
Radius of cone= 3 cm
Height of cone= 4 cm
Volume of cone = 301.44 cm cube
Answer - - - -
Radius = 3 cm (given)
Slant height=
![\sqrt[ {l}^{2} ]{ {r}^{2} + {h}^{2} } \sqrt[ {l}^{2} ]{ {r}^{2} + {h}^{2} }](https://tex.z-dn.net/?f=+%5Csqrt%5B+%7Bl%7D%5E%7B2%7D+%5D%7B+%7Br%7D%5E%7B2%7D++%2B++%7Bh%7D%5E%7B2%7D+%7D+)
![{l}^{2} \sqrt{ {3}^{2} + {4}^{2} } {l}^{2} \sqrt{ {3}^{2} + {4}^{2} }](https://tex.z-dn.net/?f=+%7Bl%7D%5E%7B2%7D++%5Csqrt%7B+%7B3%7D%5E%7B2%7D+%2B++%7B4%7D%5E%7B2%7D++%7D+)
![{l}^{2} \sqrt{9 + 16} {l}^{2} \sqrt{9 + 16}](https://tex.z-dn.net/?f=++%7Bl%7D%5E%7B2%7D+++%5Csqrt%7B9+%2B+16%7D+)
![{l}^{2} \sqrt{25} {l}^{2} \sqrt{25}](https://tex.z-dn.net/?f=+%7Bl%7D%5E%7B2%7D++%5Csqrt%7B25%7D+)
![l = 5 l = 5](https://tex.z-dn.net/?f=l+%3D+5)
Hope it will help you
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Radius of cone= 3 cm
Height of cone= 4 cm
Volume of cone = 301.44 cm cube
Answer - - - -
Radius = 3 cm (given)
Slant height=
Hope it will help you
Please mark me as brainliest
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