Question

The radius of a 80cm wide road roller is 77cm.Calculate the number of revolutions that the roller will take to cover an area of 96.8 m2.

Answer 1

Answer:

25 revolutions

Step-by-step explanation:

96.8$m^{2}$ to $cm^{2}$

= 96.8 × 10000

= 968000 $cm^{2}$

curved surface area = 2 x  x 80 x 77            

                                 = 38720 cm2                    

Number of revolutions =  $\frac{968000}{38720}$                        

                                        =  25  revolutions

Answer 2

The number of revolutions that the roller will take is 25.

Step-by-step explanation:

Given : The radius of a 80 cm wide road roller is 77 cm.

To find : Calculate the number of revolutions that the roller will take to cover an area of 96.8 m² ?

Solution :

Radius of road roller =77 cm = 0.77 m

Height of road roller = 80 cm = 0.8 m

The curved surface area  of roller is $CSA=2\pi \: rh$

$CSA=2\times \frac{22}{7}\times 0.77\times 0.8$

$CSA=3.872\ m^2$

The roller will take to cover an area of 96.8 m².

$\text{Number of revolutions}= \frac{\text{Total Area}}{\text{Curved Surface area}}$

$\text{Number of revolutions}= \frac{96.8}{3.872}$

$\text{Number of revolutions}= 25$

Therefore, the number of revolutions that the roller will take is 25.

#Learn more

A cylindrical roller has a radius of 20 cm and is 77 cm long find the area levelled by this roller in 500 revolution

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