Question

the radius of a circle is 10 cm the length of the cord is 16 cm find the distance of the from the centre​

Answer 1

Answer:

6 cm

Let the distance be X

Let the centre of the circle be 'O'

Radius=OA=10cm

Chord of circle=16 cm=PA

We need to find the distance of the chord from the centre which is the perpendicular from centre to the chord.

We know that perpendicular from centre on chord bisect the chord.

So, AQ=8 cm

Let the perpendicular be OQ

We obtain a right triangle ∆OQA

Using Pythagoras theorem

AO²=AQ²+OQ²

10²=8²+X²

X²=√(100-64)

X=√36

X=6 cm

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