Question

the radius of a circle is 10cm and the length of a chord is 12cm then distance of the chord from the center is______​

Answer 1

Answer:

By applying Pythagoras theorem we get

AC²=AB²+BC²

=(10²)+(12²)

=100+144

=244

Therefore AC=✓244

hope it is correct .

Answer 2

Answer:8 cm

Construction:join OP as such angle OPB is right angeled;i.e perpendicular

Step-by-step explanation:In right angeled triangle OPB,

By pythagoras theorem,

OP²=OB²- PB²

OP²=100-6² (since OP bisects AB)

OP=8 cm