Question

The radius of a circle is 13 cm and length of one of its chord is 10 cm. Find the distance of the chord from the centre.

Answer 1

12 cm is the distance between the centre and the

Answer 2

Refer to attached image

Suppose PR be a chord with centre Q and radius 13 cm

Hence

QP = 13cm and PR = 10cm

Perpendicular from the centre bisects the chord

Therefore

PO = $\bf\huge\frac{1}{2}AB$

PO = $\bf\huge\frac{1}{2}\times10$

PO = 5cm

From Right triangle QOP

QP^2 = QO^2 + PO^2

QO^2 = (QP^2 - PO^2)

QO^2 = (13)^2 - (5)^2

QO^2 = 144

QO = √144

QO = 12 cm

Distance of chord from the centre is 12 cm