the radius of a circle is 13 cm and lengths of one of its cord is 10cm. the distance
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Answer:
12 cm
Step-by-step explanation:
when we join the ends of the chord with centre a triangle is formed with sides 10 ,13 ,13 i.e chord (10cm) as base and radius (13cm) as others two sides , now draw a line from centre to midpoint of the chord , it forms a right angled triangle with radius (13cm) as hypotenuse and base (5cm) and assume remaining as x
now pythogorian therom
13×13=(5×5) + (x×x)
169=25 +(x×x)
(x×x) = 169-25
x=12cm
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