Question

The radius of a circle is 13 cm and the length of one of chord is 10 cm. Find the distance of the chord from the centre. ​

Answer 1

Answer:

Step-by-step explanation:

1.  Let the name of radius be OY and that of the chord be AB.

2. Draw a perpendicular line from the centre of the circle to the chord AB. Since the perpendicular line from the centre of the circle bisects the chord (theorem), name the midpoint as M.

3. Join O to B. Thus a right angled  ΔOMB is formed.

4. so by pythagoras theorem,

   (OM)² + (MB)² =   (BO)²

   (OM)² + (5)²    =   (13)²

   (OM)² + 25     =   169

               (OM)²  =  169-2

              (OM)     = √144

               OM      = 12.

∴ The distance of the chord from the centre of the circle is 12             cm.