Question

the radius of a circle is 13 cm and the length of one of its chords is 10 cm. what is the distance of the chord from the centre?

Answer 1

perpendicular drawn from the centre of the circle to the chord bisects the chord.








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Answer 2

Refers to the attachments

Let AB be a chord of a circle With centre O.

Hence, OA (radius) = 13 cm and AB = 10 cm.

The Perpendicular from the centre to a chord bisects the chord.

∴ AL = 1/2 × AB

= 1/2 × 10

= 5 cm

In right triangle OLA,

OA² = OL² + AL²

⇒ 13² = OL² + 5²

⇒ OL² = 13² - 5²

⇒ OL² = 169 - 25

⇒ OL² = 144

⇒ OL = 12 cm

The distance of the chord from the centre is 12 cm.