the radius of a circle is 13cm and the length of one of its chord is 10cm. find the distance of chord from centre. plz give me the ans with the solution
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Let OA is a radius . And OB is perpendicular to the chord AC and divides it into two equal parts AB and BC.
Now in triangle AOB
OA sq. = AB sq. + OB sq.
13 sq. = 5sq. +OB sq.
169-25 = OB sq.
144underroot = OB
12 = OB distance from the centre of the circle
Now in triangle AOB
OA sq. = AB sq. + OB sq.
13 sq. = 5sq. +OB sq.
169-25 = OB sq.
144underroot = OB
12 = OB distance from the centre of the circle
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