the radius of a circle is 17.0 cm and the length of perpendicular drawn from its centre to a chord is 8.o cm . calculate the length of the chord
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Let the radius be hypotenuseand lengh be base
h^2= P^2+B^2
17×17=8×8+b^2
289=64+b^2
289-64=b^2
√255=b
B=15
then the lengh of the chord be 15+15=30cm
h^2= P^2+B^2
17×17=8×8+b^2
289=64+b^2
289-64=b^2
√255=b
B=15
then the lengh of the chord be 15+15=30cm
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1
Answer:
it can be done by the phythogrsa therom
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