The radius of a circle is 6 cm . Find the area of the segment whose arc is of measure 120*
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The area of the circle is (pi)r^2 or (22/7)*21*21 = 1386 sq cm. The chord in the segment subtends 120 degrees at the centre of the circle. So the area of the segment is (120/360)*1386 = 1386/3 =462 sq cm.
agritjangi123:
you find sector area not segment
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2
Answer:
22cm^2
Step-by-step explanation:
Area of sector=264/7cm^2.
Area of ∆CAB =9√3cm^2.
Area of segment ABX=264/7-9√3
37.7-15.6
=22 sq. cm ( app.)
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