The radius of a circle with centre at origin is 30 units. Write the coordinates of the points where the circle intersects the axes. Find the distance between any two such points.
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as you know, distance between centre and point lies on circle be always constant which is known as radius of circle.
in figure , it is clearly shown that circle intersects the co-ordinate axes at four points.
and that are (30,0) , (-30,0) ,(0,30) and (0,-30).
now, distance between (30,0) and (0,30) = √{(30-0)² + (0 - 30)²} = 30√2 unit
similarly , you can find distance between any such two points.
for better understanding, let A = (30,0) , B=(0,30) , C = (-30,0) and D = (0, -30)
then, Length of AB = length of BC = length of CD = length of DA = 30√2 unit
in figure , it is clearly shown that circle intersects the co-ordinate axes at four points.
and that are (30,0) , (-30,0) ,(0,30) and (0,-30).
now, distance between (30,0) and (0,30) = √{(30-0)² + (0 - 30)²} = 30√2 unit
similarly , you can find distance between any such two points.
for better understanding, let A = (30,0) , B=(0,30) , C = (-30,0) and D = (0, -30)
then, Length of AB = length of BC = length of CD = length of DA = 30√2 unit
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Step-by-step explanation:
1+1=2
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