The radius of a circle with centre 'O' is 13cm. the distance of a chord from the centre is 5cm. find the length of the chord
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P be the mid point of AB, So
AP = PB
OP = 5cm = distance of chord from center
And
AO = 13 cm = Radius
Now, OPA forms a right angle triangle.
Now, by pythagorous theorem,
AO2 = OP2 + AP2
AP2 = AO2 - OP2
AP2 = 169-25
=144 =12 Now chord=12+12 =24cm
AP = PB
OP = 5cm = distance of chord from center
And
AO = 13 cm = Radius
Now, OPA forms a right angle triangle.
Now, by pythagorous theorem,
AO2 = OP2 + AP2
AP2 = AO2 - OP2
AP2 = 169-25
=144 =12 Now chord=12+12 =24cm
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