The radius of a circular ends of a bucket of height 24cm are 15 cm and 5 cm find the area of its curved surfac
Answers
Answered by
1
Hey frnd,here is ur answer:
h=24cm r1=15cm r2=5cm
CSA of frustum=πl(r1+r2)
l=√h sq+(r1-r2)sq
l=√24x24+(15-5)sq
l=√576+100
l=√676
l=26cm
CSA=3.14x26(15+5)
=81.64x20
=1632.8cm sq
Answered by
3
Answer:
1634.3 cm² .
Step-by-step explanation:
Let radii be R and r .
It is given R = 15 cm , r = 5 cm and h = 24 cm
We know slant height :
l = [ √ h² + ( R - r )² ]
l = √ 24² + 10²
l = 26 cm .
Now ,
C.S.A. = π ( R + r ) l
= 3.14 × 20 × 26 cm²
= 1634.3 cm² .
Similar questions