the radius of a circular Park is 56 metre if a road 3.5 metre wide is made around its on the outside find the cost of construction The Road at the rate of rupees 25 per square meter
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First the area of the circular park
= Pi r^2
=22/7*56^2
=22/7*3136
=22*448
=9856 metre square
Area of park along with road
Then radius of park along with the road
=56+3.5
=59.5metres
Therefore area of park along with the road
= Pi r^2
=3.14*59.5^2
=3.14*3540.25
=11116.385 metre square
Therefore the area of the road =
Area of park along with the road -area of park
=11116.385-9856
=1260.385 metre square
Cost of construction of road
=area of road *25
=1260.385*25
=Rs. 31509.625
= Pi r^2
=22/7*56^2
=22/7*3136
=22*448
=9856 metre square
Area of park along with road
Then radius of park along with the road
=56+3.5
=59.5metres
Therefore area of park along with the road
= Pi r^2
=3.14*59.5^2
=3.14*3540.25
=11116.385 metre square
Therefore the area of the road =
Area of park along with the road -area of park
=11116.385-9856
=1260.385 metre square
Cost of construction of road
=area of road *25
=1260.385*25
=Rs. 31509.625
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