Math, asked by swaroopsunil8596, 9 months ago

The radius of a cylindrical milk container is half its height and surface area of the inner part is 616 sq.Cm. The amount of milk that the container can hold, approximately, is [ use : 5 = 2.23 and = 22/7 ]

Answers

Answered by nasaanirudh
0

Answer:

Volume of cylinder = π*r*2*h

v = π*r*2*(2*r) = 2* π*r*3 (∵ = 2*r )

Curve Surface area = 2 π r*h

= 2 *π *r (2*r) = 4 *π*r*2

4* π* r* 2 = 616

r * 2 = 49 => r = 7

∴ V = 2 *π *(7)*3 = 2156 cm^3

= 2.156 liters = 2.2 liters

∴,the milk container can store 2.2 L of milk.

Answered by TanikaWaddle
0

The amount of milk that the container can hold is 2.3 liters

Step-by-step explanation:

here ,

volume of cylinder = \pi r ^2 h

h = 2r

therefore ,

V = \pi r ^2 (2r) = 2\pi r^3

now, curved surface area of the cylinder = 2\pi rh

2\pir(2r)= 4\pir^2\\\\4\pir^ = 616 \\\\r^2 = 49\\\\r = \sqrt{49}\\\\r = 7

thus the value of r = 7 cm

now , put the value of r in volume

V = 2\pi r^3 \\\\V = 2 \times \frac{22}{7}\times (7)^3 \\\\V = 2156 cm^3

converting into liters

we get

Volume = 2.156 liters ≈ 2.2 liters

hence , The amount of milk that the container can hold is 2.3 liters

#Learn more :

A container is in the shape of a cylinder of inner radius 7 m and height 60 m find the cost of milk if the container is filled with milk if the container is filled with milk and sold at rs. 20 per liter

https://brainly.in/question/14507286

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