The radius of a metallic sphere is 9 cm. It was melted to make a wire of diameter 4 mm. Find the length of the wire.
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Answered by
6
Hi ,
1 ) Radius of the metallic Sphere ( R )
= 9 cm
If it is melted and cast into a wire ,
Diameter of the wire ( d ) = 4 mm
Radius of the wire ( r ) = d/2
r = 4/2 = 2 mm = ( 2/10 )cm
r = 1/5 cm
let the length of the wire = h cm
Volume of the wire = volume of the
Sphere
πr² h = ( 4πR³)/3
h = ( 4πR³ )/(3πr² )
h = ( 4R³ )/3r²
h = ( 4 × 9 × 9 × 9 )/(3 × 1/5 × 1/5 )
h = ( 4 × 9 × 9 × 3 × 5 × 5 )
h = 24300 cm
Therefore ,
Length of the wire = h = 24300cm
I hope this helps you.
: )
1 ) Radius of the metallic Sphere ( R )
= 9 cm
If it is melted and cast into a wire ,
Diameter of the wire ( d ) = 4 mm
Radius of the wire ( r ) = d/2
r = 4/2 = 2 mm = ( 2/10 )cm
r = 1/5 cm
let the length of the wire = h cm
Volume of the wire = volume of the
Sphere
πr² h = ( 4πR³)/3
h = ( 4πR³ )/(3πr² )
h = ( 4R³ )/3r²
h = ( 4 × 9 × 9 × 9 )/(3 × 1/5 × 1/5 )
h = ( 4 × 9 × 9 × 3 × 5 × 5 )
h = 24300 cm
Therefore ,
Length of the wire = h = 24300cm
I hope this helps you.
: )
Answered by
4
Heya !!
Radius of metallic sphere ( R ) = 9 cm
Therefore,
Volume of metallic sphere = 4/3 πR³
=> 4/3 × 22/7 × 9 × 9 × 9
=> ( 4 ×22 × 3 × 9 × 9 ) / 7
=> 21384/7 cm³.
Diameter of wire ( D ) = 4 mm
Radius ( R 1 ) = D/2 = 4/2 = 2 mm = 2/10 cm = 1/5 cm.
Therefore,
Volume of wire = πR²H
=> 22 / 7 × 1/5 × 1/5 × H
=> ( 22 × 1 × 1 × H ) / ( 7 × 5 × 5 )
=> 22H/175
Volume of metallic sphere = Volume of wire
21384/7 = 22H/175
22H = ( 21384 × 175)/7
22H = 534600
H = 534600/22 = 24300 cm.
Hence,
Length of wire = H = 24300 cm.
Radius of metallic sphere ( R ) = 9 cm
Therefore,
Volume of metallic sphere = 4/3 πR³
=> 4/3 × 22/7 × 9 × 9 × 9
=> ( 4 ×22 × 3 × 9 × 9 ) / 7
=> 21384/7 cm³.
Diameter of wire ( D ) = 4 mm
Radius ( R 1 ) = D/2 = 4/2 = 2 mm = 2/10 cm = 1/5 cm.
Therefore,
Volume of wire = πR²H
=> 22 / 7 × 1/5 × 1/5 × H
=> ( 22 × 1 × 1 × H ) / ( 7 × 5 × 5 )
=> 22H/175
Volume of metallic sphere = Volume of wire
21384/7 = 22H/175
22H = ( 21384 × 175)/7
22H = 534600
H = 534600/22 = 24300 cm.
Hence,
Length of wire = H = 24300 cm.
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