the radius of a metallic sphere is 9cm. it was melted to make a wire of diameter 4 mm find the length of the wire
vikram991:
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Answers
Answered by
46
Volume of sphere = 4/3 πr³
Find the volume:
Volume of the sphere = 4/3 π (9)³
Volume of the sphere = 972π cm³
Find the radius:
Radius = Diameter ÷ 2
Radius = 4 ÷ 2
Radius = 2mm = 0.2 cm
Find the length of the wire:
πr²h = Volume
π(0.2)² h = 972π
0.04πh = 972π
h = 972π ÷ 0.04π
h = 24300 cm
Answer: The length of the wire is 24300 cm
Answered by
19
here is your answer OK dude........
DonDjAce
HERE IS YOURS SOLUTION;
◆ Let R = radius of the sphere;
◆ Now, R = 9 cm;
Volume of sphere, V1 = 43πR3 = 43π(9)3 = 972π cm3.
◆ Now, diameter of the wire = 2 mm = 0.2 cm [as 1 cm = 10 mm]
radius of the wire, r = 0.1 cm
◆ Let h = length of the wire
volume of cylinderical wire, V2 = πr2h = (0.1)2πh cm3
◆ Since the sphere is melted and recast into wire, so in this case volume of the material remains same.
So, V2 = V1
⇒(0.1)2πh = 972π
⇒0.01 h = 972
⇒h = 97200 cm
⇒h = 972 m. [ 1 M = 100 Cm]
◆ So, the length of the wire is 972 M ◆
HOPE IT HELPS
DonDjAce
HERE IS YOURS SOLUTION;
◆ Let R = radius of the sphere;
◆ Now, R = 9 cm;
Volume of sphere, V1 = 43πR3 = 43π(9)3 = 972π cm3.
◆ Now, diameter of the wire = 2 mm = 0.2 cm [as 1 cm = 10 mm]
radius of the wire, r = 0.1 cm
◆ Let h = length of the wire
volume of cylinderical wire, V2 = πr2h = (0.1)2πh cm3
◆ Since the sphere is melted and recast into wire, so in this case volume of the material remains same.
So, V2 = V1
⇒(0.1)2πh = 972π
⇒0.01 h = 972
⇒h = 97200 cm
⇒h = 972 m. [ 1 M = 100 Cm]
◆ So, the length of the wire is 972 M ◆
HOPE IT HELPS
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