Question

The radius of a one circular field is 20 m and that of another is48 m. Find the radius of the third circular field whose area is equal to the sum of the areas of two field

Answer 1

Heya frnd,
here is your answer


given,
radius of 1st circle = r = 20m
radius of 2nd circle = r' = 48m

as we know the formula for area of a circle= Πr² , where Π = 22/7

so area of 1st circle
= Πr²
= 22/7 × (20)²
= 22/7 × 20 × 20
= 8800/7 m²

area of 2nd circle
= Π(r')²
= 22/7 × (48)²
= 22/7 × 48 × 48
= 50688/7 m²

sum of area of both the circles
= 8800/7 + 50688/7
= 59488/7 m²

according to the question,
let the radius of the 3rd circle = r"
then,

area of the 3rd circle = 59488/7

=> Π(r")² = 59488/7

=> 22/7 × (r")² = 59488/7

=> (r")² = 59488/7 × 7/22

=> (r")² = 2704

=> r" = √2704
= 52m


Hence the radius of the new circle is 52m




Hope this help

if u need any further help, ask me i would try to help you


Thank you


#Sneha

Answer 2

Answer:

Step-by-step explanation:

Area of the 3rd circle =59488/7

=(r")^2=59488/7

=(r")^2=59488/7×7/22

=(r")^2= 2704

=r"=underroot2704

=52m