The radius of a roller is 49cm and its length is 125 cm how much atea of playground will be levelled in 400 revolutions moving one over the ground
Answers
1540 m² area of the playground will be levelled in 400 revolutions moving one over the ground.
Step-by-step explanation:
Formula Used:
- CSA of cylinder = 2πrh
The radius of a roller, r = 49 cm
The length of the roller i.e., the height of the cylinder, h = 125 cm
We know that,
[The distance covered by the roller in 1 revolution] = [Curved Surface Area of the cylinder] = 2πrh
⇒ The distance covered by the roller in 1 revolution is,
= 2 * 22/7 * 49 * 125
= 38500 cm²
Thus,
The distance covered by the roller in 400 revolutions is given by,
= 400 * 38500 cm²
= 15400000 cm²
Since 1 cm² = 1/10000 m²
= 1540 m²
-------------------------------------------------------------------------------------------
Also View:
The radius of a roller is 60 cm and its length is 84cm find the area of the ground pressed by it in 500 revolution?
https://brainly.in/question/7015998
The diameter of a roller is 42 cm and its length is 100 cm. it takes 400 complete revolutions moving once over the level of a playground . determine the area of the playground. also,find the cost of leveling the playground a rs50 per 105sqm?
https://brainly.in/question/2787475