Question

The radius of a roller is 7 m and its length is 10 m. The area levelled by it in 200 revolutions will be​

Answer 1

Answer:

$\bigstar{\bold{Area\:levelled=88000\:m^{2} }}$

Step-by-step explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Radius(r) = 7 m
• Length = 10 m
• Revolutions = 200 revolutions

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• The area levelled by it

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ Here the roller is in the shape of a cylinder.

→ Hence the area covered by it = CSA of the cylinder

→ CSA of a cylinder is given by the formula,

   CSA of a cylinder = 2 π r h

→ Here height of the cylinder = length of the cylinder

→ Substitute the given datas in the above equation

   CSA of cylinder = 2 × 22/7 × 7 × 10

   CSA of the cyllinder = 2 × 22 × 10

   CSA of cylinder = 440 m²

→ Area levelled by it =  CSA of cylinder

→ Area levelled by it =  440 m²

→ Hence

  Area levelled in 200 revolutions = 440 × 200

  Area levelled in 200 revolutions = 88000 m²

$\boxed{\bold{Area\:levelled=88000\:m^{2} }}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ CSA of a cylinder = 2 π r h

→ TSA of a cylinder = 2 π r (r + h)

→ Volume of cylinder = π r² h