the radius of a sphere is 10 cm if the radius in is increased by 1 cm then prove that volume of the sphere is interest by 33.1%
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vol. of sphere =4/3 πr^3
r=10 cm
vol,v1= (4/3π)1000
when r is inc. by 1cm new radius =11
vol,v2=(4/3π)13331
now percent change =(v2-v1)/v1
=(331/1000) *100
=33.1%
r=10 cm
vol,v1= (4/3π)1000
when r is inc. by 1cm new radius =11
vol,v2=(4/3π)13331
now percent change =(v2-v1)/v1
=(331/1000) *100
=33.1%
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