Math, asked by rizwanjigger, 1 month ago

The radius of a sphere is increased by 10%. The surface area increases by:​

Answers

Answered by dorardhanesh
0

Answer:

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Step-by-step explanation:

Let radius of sphere=r

Volume=

3

4

πr

3

Radius is increased by 10 %=r+

100

10

r

=r+

10

r

=

10

11r

Volume =

3

4

π×

1000

11

3

r

3

Increased volume %=

3

4

πr

3

(

1000

1331

−1)

3

4

πr

3

×100

=

1000

331

×100=33.1%

∴Volume increased by 33.1%

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