Question

The radius of a wire is decreased to one-third .If volume remains the same, then how many times the length of wire is increased?

Answer 1

↑ Here is your answer ↓
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We knows that wire is in the shape of a cylinder.
So, volume of wire = $\pi r^2h$

$\pi r^2h$ = $\pi (r/3)^2h$

$\pi r^2h$ = $\pi \frac{r^2}{9} h$

Cancelling π on both sides,

$r^2h = \frac{r^2}{9} h$

$9r^2h = r^2h$

Now cancelling 'r²' on both sides, we get

$9h = h$

So, height is increased by 9 times.

Answer 2

I hope this will help you