the radius of an air bubble is increasing at the rate of 0.5 centimetre per second find the rate of change of its volume when the radius is 1 cm
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v= 4/3 πr^3 then dv/ dt = 4/3π × 3r^2 ×dr/dt then putting value so ans is 2π
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Answer:Dr/dt=0.5cm|sec
V=4/3πr r r
Dv/dt = 4/3 π r r 3Dr /dt
2πrr
Put the value of r and divide by 5 answer is 0.4 cm cube per sec
Step-by-step explanation:
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