Question

rationalize the denominator 1/ 3+root 2

Answer 1

$\frac{1}{3 + \sqrt{2} }$


By Rationalization,


$\frac{1}{3 + \sqrt{2} } \times \frac{3 - \sqrt{2} }{3 - \sqrt{2} } \\ \\ \\ = > \frac{3 - \sqrt{2} }{ {(3)}^{2} - {( \sqrt{2}) }^{2} } \\ \\ \\ = > \frac{3 - \sqrt{2} }{9 - 2} \\ \\ \\ = > \frac{3 - \sqrt{2} }{7}$