Question

plzz help me in question 6

Answer 1

initial velocity u=18 km/h=18*5/18=5m/s.
final velocity v=36 km/h=36*5/18=10m/s.
time t=5s.
a=v-u/t.
=10-5/5.
=5/5.
=1
acceleration=1m/s2.

s=ut+1/2at2.
=25+25/2.
=25+12.5.
=37.5m.
distance = 37.5 m.

Answer 2

given
u=18km/h
thus u in m/s=18*5/18=5m/s
v=36km/h
thus v in m/s=36*5/18=10m/s
t=5seconds
thus a=(v-u)/t
=(10-5)/5
=5/5
=1m/s^2
to find distance
s=ut + 1/2at^2
=5*5+1/2*1*5*5
=25+25/2
=(50+25)/2
=75/2
=37.5metres
hope it helps.......