Question

The radius of ball A is twice than that of B. What will be the ratio of their terminal velocities?

Answer 1

Answer:

The answer is 4:1.

Explanation:

As terminal velocity ∝(radius of ball)2, therefore, ratio of terminal velocities of A and B will be 4:1.

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Answer 2

Given:

The radius of ball A is twice that of B.

To Find:

The ratio of their terminal velocities.

Solution:

Let the terminal velocity of ball A be r.

Ball A and B have their ratio of radii 1:2

Now,  $\frac{r_{A} }{r_{B} }$ = 1/2

Using, $\frac{2}{9} \frac{r^{2}(p-5)g }{x}$   here p= density of the sphere

                                     б= fluid

                                      x= coefficient of velocity

                                      g= acceleration due to gravity

  $V_{A}$ = 2/9 $\frac{r_{A} ^{2} (p-5)g }{x}$

  $V_{B}$ = 2/9 $\frac{r_{A} ^{2} (p-5)g }{x}$

$\frac{V_{A} }{V_{B} } = \frac{r_{A}^{2} }{R_{B}^{2} }$ =1/4

$V_{A}:V_{B}$ = 1:4

Therefore, the ratio of their terminal velocities = 1:4