the radius of circle with Centre P is 25 CM the length of chord of same circle is 48 cm find the distance of the chord from the centre p
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Let the distance PC from centre P to chord AB be x.
AP² = PC² + AC²
(25)² = (x)² + (48/2)²
625 = x² + (24)²
625 = x² + 576
x² = 625 - 576
x² = 49
x = √49
x = 7 cm
AP² = PC² + AC²
(25)² = (x)² + (48/2)²
625 = x² + (24)²
625 = x² + 576
x² = 625 - 576
x² = 49
x = √49
x = 7 cm
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