Question

The radius of curvature (in m) of a projectile at highest point when projected with a speed of 20 m/s at an angle of 60° with the horizontal is?​

Answer 1

Answer:

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Answer 2

Concept:

The formula that can calculate the radius of curvature is expressed as,  r = v²cos²θ / g

Given:

speed = 20m/s

angle, θ = 60⁰

Find:

We need to determine the radius of curvature, r of a projectile.

Solution:

The radius of a circular arc that most closely resembles the curve at a given point along a projectile's trajectory is the radius of that point's trajectory, which reveals how the projectile's trajectory is curving.

The radius of curvature is given by the formula, r = v²cos²θ / g

For instance, if the radius of curvature is smaller at the top (the point of most height), it will curve more there than, say, at the launch or landing point, where it will curve less.

We have been given that the speed i.e. velocity is 20m/s, angle as 60⁰ and g is to be taken as 9.8 m/s²

Therefore, formula becomes-

r = v²cos²θ / g

r = 20² × cos²60 / 9.8

r = 400 × (1/2)² / 9.8

r = 100 / 9.8

r = 10.2m

Thus, The radius of curvature (in m) of a projectile at the highest point is 10.2m.

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